The reaction of nitric oxide (NO(g)) with molecular hydrogen (H2(g)) results in the production of molecular nitrogen

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The reaction of nitric oxide (NO(g)) with molecular hydrogen (H2(g)) results in the production of molecular nitrogen and water as follows:

2NO(g) + 2H2(g) †’ N2O(g) + 2H2O(g)

The experimentally determined rate law expression for this reaction is first order in H2(g) and second order in NO(g).

a. Is the reaction as written consistent with the experimental order dependence for this reaction?

b. One potential mechanism for this reaction is as follows:

H2(g) + 2NO(g)– →N,O(g) + H20(g) (3)0'H + (3)'N,(3)o°N + (3)H

Is this mechanism consistent with the experimental rate law?

c. An alternative mechanism for the reaction is:

2NO(3)N,0,(3) (fast) 2N,02(8) (fast) k1 H2 (g) + N202(g)-* N20(g) + H,0(g) H2(g) + N20(g)– k »N2(g) + H2O(g)

Show that this mechanism is consistent with the experimental rate law.

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Related Book For  book-img-for-question

Physical Chemistry

ISBN: 978-0321812001

3rd edition

Authors: Thomas Engel, Philip Reid

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