A rough surface has a BRDF proportional to cos( 0 )cos( 1 ), where 0 and
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A rough surface has a BRDF proportional to cos(θ0)cos(θ1), where θ0 and θ1 are respectively the angles of the incident and scattered radiation measured from the surface normal. The BRDF has no azimuthal dependence. Show that, if the albedo for normally incident radiation is 1, the diffuse albedo of the surface is 2/3.
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In section 332 it is shown that the diffuse albedo is given by whe...View the full answer
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