Question: The position of a particle is given by the function x = (2t 3 6t 2 + 12) m, where t is in s.

The position of a particle is given by the function x = (2t3 – 6t2 + 12) m, where t is in s.

a. At what time does the particle reach its minimum velocity? What is (vx)min?

b. At what time is the acceleration zero?

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First take the derivatives Every quantity is in SI units x 2t 3 6t 2 12 v 6t 2 12t 12t 12 a To ... View full answer

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