The P-value for a chi-square test for goodness of fit is 0.0129. Which of the following is the most appropriate conclusion at a significance level of 0.05?

a. Because 0.0129 is less than α = 0.05 reject H₀. There is convincing evidence that the food choices are equally popular.

b. Because 0.0129 is less than α=0.05 reject H₀. There is not convincing evidence that the food choices are equally popular.

c. Because 0.0129 is less than α = 0.05 reject H₀. There is convincing evidence that the food choices are not equally popular.

d. Because 0.0129 is less than α = 0.05 fail to reject H₀. There is not convincing evidence that the food choices are equally popular.

e. Because 0.0129 is less than α = 0.05 fail to reject H₀. There is convincing evidence that the food choices are equally popular.

The manager of a high school cafeteria is planning to offer several new types of food for student lunches in the new school year. She wants to know if each type of food will be equally popular so she can start ordering supplies and making other plans. To find out, she selects a random sample of 100 students and asks them, “Which type of food do you prefer: Ramen, tacos, pizza, or hamburgers?” Here are her data:

Select the best answer.

Transcribed Image Text:

Туре of food Ramen Таcos Pizza Hamburgers Count 18 22 39 21