Evaluate the integral. 3 x3 2 + 6 4 dx (x + 1)(x + 2)

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Evaluate the integral. Зх3 Зx3 — х2 + 6х — 4 dx (x² + 1)(x² + 2)

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Calculus Early Transcendentals

ISBN: 978-1285741550

8th edition

Authors: James Stewart

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Question Posted: Apr 09, 2019 11:48 AM

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Evaluate the integral. 3 x3 2 + 6 4 dx (x + 1)(x + 2)

Question:

Зх3 Зx3 — х2 + 6х — 4 dx (x² + 1)(x² + 2)

Step by Step Answer:

3xx 6x4 x 1x 2 Equating the coefficients gives A C 3 ...View the full answer

Calculus Early Transcendentals

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