If (x) is one-to-one and (x) is never zero, can anything be said about h(x) = 1/(x)?

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If ƒ(x) is one-to-one and ƒ(x) is never zero, can anything be said about h(x) = 1/ƒ(x)? Is it also one-to-one? Give reasons for your answer.

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Thomas Calculus Early Transcendentals

ISBN: 9780321884077

13th Edition

Authors: Joel R Hass, Christopher E Heil, Maurice D Weir

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