Show that (10.26) and (10.27) are Fourier transform pairs. In 2 (f (10.26) (f) xp 2?

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Show that (10.26) and (10.27) are Fourier transform pairs.

In 2 (f (10.26) н (f)— еxp

2л? в 2л -B exp In 2 h(t) = (10.27) In 2

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