=+11.29. This exercise is related to the expression of the histogram (see Section 11.6). (i) Show that
Question:
=+11.29. This exercise is related to the expression of the histogram (see Section 11.6).
(i) Show that (11.82) holds provided that F is twice continuously differentiable.
(ii) Show that the limit (11.81) is either zero or ∞ if F is replaced by Fˆ, the empirical d.f.
(iii) Show that the histogram is equal to the right side of (11.83) with probability 1.
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