1. Because % is a wildcard character, how can the LIKE operator search for a literal percent sign (%) in a character string?

2. If a sort is based on three columns, as shown below, how will the data below appear in the report and why? Show sorted list.

ORDER BY state, city DESC, address ASC

(unsorted below)

MA Stow 25 Main St

NY Littletown (null)

MA Bordertown 23 Pond St

MA Bordertown 1 Pond St

NY Littletown 45 Dover Ln

FL Sunnytown 88 Boulder Circle

FL Rainbow 88 Pilgrim St

(To test for Q1 above, you may want to create the following small table with the data that includes % character in the beginning, middle and end of the string. Your query or queries will find % sign in these strings)

CREATE table test (colA VARCHAR2(100)); INSERT INTO test VALUES ('% this is a string with percent in the beginning'); INSERT INTO test VALUES ('this is a string with a percent sign % in the middle'); INSERT INTO test VALUES ('this is a string with percent sign at the end %');