1. Create a class called Time, in the files "time.h" and "time.cpp", which will involve a variety of operator overloads. A Time object will store a quantity of time, in terms of days, hours, minutes, and seconds. You will overload some basic operators for use with these objects, including arithmetic, comparison, and insertion/extraction (I/O) operators. Note: These operations must work even for large time amounts (i.e. fairly large nubmers of hours) and should not overflow the capacity of the storage variables (ints) unless the actual number of hours is very close to the upper limit of int storage.

Details and Requirements:

2. The Time class must allow for storage of a non-negative quantity of time, in terms of days, hours, minutes, and seconds. The hours, minutes, and seconds portion will be expressed in the normal way that it would appear on a digital timer. Example: 18:30:58 means 18 hours, 30 minutes, 58 seconds. All values should be non-negative. The minutes and seconds values should never be over 59, and the hours should never be over 23. (i.e. if you have 61 seconds, that is really 1 minute and 1 second). The Time should always be kept in this simplified format. There is no limit on the number of days. You should create appropriate member data in your class. All member data must be private.

3. Constructors

- The class should have a default constructor (no parameters), which should initialize the object so that it represents the quantity 0.

- The class should also have a constructor with a single integer parameter, which represents a quantity of seconds -- which should be translated into the appropriate notation for a Time object. Note that this constructor with a single parameter will be a "conversion constructor" that allows automatic type conversions from "int" to "Time". If the parameter is negative, default the Time object to represent 0.

- The class should also have a constructor that takes 4 parameters, representing the days, hours, minutes, and seconds to use for initializing the object. If any of the provided values are negative, default the Time object to represent 0. If any of the provided values are too high (but all non-negative), simplify the object to the appropriate representation

Examples:

 Time t; // this creates an object which is 0 days, 0 hours, 0 minutes, 0 seconds Time s(1234); // this creates an object representing 0 days, 0 hours, 20 minutes, 34 seconds Time r(-123); // creates an object representing 0 days, 0 hours, 0 minutes, 0 seconds t = 4321; // conversion constructor allows this assignment. // t now stores 0 days, 1 hour, 12 minutes, 1 second Time x(1, 3, 5, 7); // 1 day, 3 hours, 5 minutes, 7 seconds Time y(2, -4, 6, 8); // creates object representing 0, since -4 hours not legal Time z(2, 25, 4, 62); // 3 days, 1 hour, 5 minutes, 2 seconds (simplified) 

4. Create an overload of the insertion operator << for output of Time objects. A time object should be printed in the format: days~hh:mm:ss -- where days is the number of days, and the hours, minutes, and seconds values are all expressed in two digits, as they would be on a digital stopwatch or timer. Examples:

10~12:23:48 means 10 days, 12 hours, 23 minutes, 48 seconds

123~04:02:33 means 123 days, 4 hours, 2 minutes, 33 seconds

5. Create an overload of the extraction operator >> for reading Time objects from an input stream. The format for the input of a Time object is the same as the output format listed above. This operator will need to do some error checking, as well. If any of the input values are negative, this is an illegal Time quantity, and the entire object should default to the value 0 (0 days, hours, minutes, seconds). If any of the values are over the allowable limit (i.e. not in simplified form), then this function should adjust the Time object so that it is in simplified form. Example: If the input object is "10~26:05:61", then it should be simplified to "11~02:06:01" since 61 seconds is really "1 minute, 1 second", and 26 hours is really "1 day, 2 hours".

6. Create overloads for the + operator and the - operator to allow addition and subtraction of two quantities of time. Results should always be returned in the simplified form. For subtraction, if the first quantity of time is less than the second (which would normally result in a negative quantity), return the Time object 0~00:00:00 instead. Examples:

2~04:07:28 + 5~08:19:02 = 7~12:26:30

2~04:07:28 - 5~08:19:02 = 0~00:00:00

5~12:15:57 + 2~16:51:05 = 8~05:07:02

5~12:15:57 - 2~16:51:05 = 2~19:24:52

7. Create an overload for the * operator, to allow a Time object to be multiplied with an integer multiplier. The result should be expressed in simplified format. Examples:

Time t1(2,7,10,32); // 2~07:10:32 cout << t1 * 2; // t1 * 2 yields: (4~14:21:04) cout << t1 * 5; // t1 * 5 yields: (11~11:52:40) 

8. Create overloads for all 6 of the comparison operators ( < , > , <= , >= , == , != ). Each of these operations should test two objects of type Time and return true or false. You are testing the Time objects for order and/or equality based on whether one quantity of time is more than (less than, equal to, etc) another.

9. Create overloads for the increment and decrement operators (++ and --). You need to handle both the pre- and post- forms (pre-increment, post-increment, pre-decrement, post-decrement). These operators should have their usual meaning -- increment will add 1 second to the Time value, decrement will subtract 1 second. If the time object is already at 0, then decrement doesn't change it (i.e. you still never will have a negative time value). Examples:

 // suppose t1 is 2~04:07:58 // suppose t2 is 5~08:19:01 cout << t1++; // prints 2~04:07:58, t1 is now 2~04:07:59 cout << ++t1; // prints 2~04:08:00, t1 is now 2~04:08:00 cout << t2--; // prints 5~08:19:01, t2 is now 5~08:19:00 cout << --t2; // prints 5~08:18:59, t2 is now 5~08:18:59 

General Requirements

no global variables

All member data of the Time class must be private

only library is iostream

Local changes to output formatting streams should remain local