1. Determine the volume of base used: Vhese=VAuer2VAasi1=VNsO 2. Determine the volume of acid used: Vocit=VmewnVond=VSNG10,204250= 3. The talanced equation for the acid base reaction is: NaOH(aq)+HCl(aq)H2O(l)+NaCl(aq) (2) 1 mole base reacts with 1 mole acid so at the equivalence poiat, moles NaOH= moles HCl. The endpoint was measured here bur it should be very close to the equivalence point. 4. The concentration of the acid can be found 2 ways:- A. Stoichiometry4 i. Find the number of moles of base ured: moles (NaOH)=MNONMVNsOH i. Find the number of moles of acid using eqn (2): moles (NaOH)(NaOHIHCl)=moles(HCl) iii. Find the concentration of acid by dividing by the volume of acid [HCl]=VHCImoles(HCl B. Using the relationship: MOWVOY=MBVH 1. Rearrange the formula: MM=VHMOHVOH i. Plag in the values and solve. Experiment 2 . This is a linte trickier because the overall reaction is: Na2B4O7(aq)+2HCl(aq)+5H2O(t)2NaCl(aq)+4H3BO3(aq) Here, wice as much HCl is required for a given amocnt of Borax. 2. Determine the volume of acid used: Vacal=VacinVarial=VBC 3. To Solve by Stoichiometry? A. Stoichiometry i. Find the number of moles of acid used: moles(HCl)=MHCVHCl ii. Find the number of moles of base used using eon (3) moles (HCl)(2HClHC1Na2B4O7)=moles(Na2B4O7) iii. Find the concentration of sodium tetra borate base by dividing by the volume of base: [Na2B4O7]=Vburmoles(Na2B4O7) B. Using the relationship: MOHVON=MHVH is harder because the balanced eqn, shows 1Na2B4O7(aq):2HCl(aq) so MOH=2(MNat2H6O3) I. Rearrange the formula: MOH=VOIMHVII 1. Determine the volume of base used: Vhese=VAuer2VAasi1=VNsO 2. Determine the volume of acid used: Vocit=VmewnVond=VSNG10,204250= 3. The talanced equation for the acid base reaction is: NaOH(aq)+HCl(aq)H2O(l)+NaCl(aq) (2) 1 mole base reacts with 1 mole acid so at the equivalence poiat, moles NaOH= moles HCl. The endpoint was measured here bur it should be very close to the equivalence point. 4. The concentration of the acid can be found 2 ways:- A. Stoichiometry4 i. Find the number of moles of base ured: moles (NaOH)=MNONMVNsOH i. Find the number of moles of acid using eqn (2): moles (NaOH)(NaOHIHCl)=moles(HCl) iii. Find the concentration of acid by dividing by the volume of acid [HCl]=VHCImoles(HCl B. Using the relationship: MOWVOY=MBVH 1. Rearrange the formula: MM=VHMOHVOH i. Plag in the values and solve. Experiment 2 . This is a linte trickier because the overall reaction is: Na2B4O7(aq)+2HCl(aq)+5H2O(t)2NaCl(aq)+4H3BO3(aq) Here, wice as much HCl is required for a given amocnt of Borax. 2. Determine the volume of acid used: Vacal=VacinVarial=VBC 3. To Solve by Stoichiometry? A. Stoichiometry i. Find the number of moles of acid used: moles(HCl)=MHCVHCl ii. Find the number of moles of base used using eon (3) moles (HCl)(2HClHC1Na2B4O7)=moles(Na2B4O7) iii. Find the concentration of sodium tetra borate base by dividing by the volume of base: [Na2B4O7]=Vburmoles(Na2B4O7) B. Using the relationship: MOHVON=MHVH is harder because the balanced eqn, shows 1Na2B4O7(aq):2HCl(aq) so MOH=2(MNat2H6O3) I. Rearrange the formula: MOH=VOIMHVII