1) Find the value of the test statistic zfor the given information below.

The claim is that the proportion of adults who shop using the Internetis less than 0.5, and the sample include n = 1025 subjects with 29% saying that they use the Internet for shopping.

2) Find the p-value for the given information below.(round to 4 decimals).

(a) H₁: p>0.29, the test statistic is z=1.97

(b) Right-tailed test is z=0.55

(c) H₁ : p 0.30, the test statistic is z= 2.44

(d) Left-tailed test is z= -1.72

3)Find the critical z value(s). Assume that the normal distribution applies.

(a) = 0.10; H₁ is p>0.18

(b)= 0.02; H₁ is p<0.19

(c)= 0.10; H₁ is p 0.17

(d) Right-tailed test: = 0.01

(e) Two-tailed test: = 0.01

4) REJECTorFAIL TO REJECTthe null hypothesis. Glamourmagazine sponsored a survey of 2500 prospective brides and found that 60% of them spent less than $750 on their wedding gown. Use a 0.01 significancelevel to test the claim that less than 62% of brides spend less than $750 on their wedding gown.

5) REJECTorFAIL TO REJECTthe null hypothesis.

z= 1.85

Critical Value= 1.96

P-value=0.3346

Significance Level= 0.05

6) REJECTorFAIL TO REJECTthe null hypothesis. In recent year, of the 109,857 arrests for Federal offenses, 29.1% were for drug offenses (based on data from the U.S. Department of Justice). Use a 0.01 significancelevel to test the claim that the drug offense rate is equal to 30%.

7) Find the value of the test statistic for the given information below.

(a) Claim:The mean IQ score of statistics professors is greater than 118.

Sample Data:n =20, X=120, s =12.The significance level is=0.05.

(b) Claim:The mean time between uses of a TV remote control by males during commercials equal 5.00 sec.

Sample Data:n =81,X=5.25, s =2.50 sec.The significance level is=0.01.