1. Jane wants to estimate the proportion of students on her campus who eat cauliflower. After surveying 31 students, she finds 5 who eat cauliflower. Obtain and interpret a 90% confidence interval for the proportion of students who eat cauliflower on Jane's campus using Agresti and Coull's method.

Construct and interpret the 90% confidence interval. Select the correct choice below and fill in the answer boxes within your choice.

(Round to three decimal places as needed.)

A.The proportion of students who eat cauliflower on Jane's campus is between nothing and nothing 90% of the time.

B. There is a 90% chance that the proportion of students who eat cauliflower on Jane's campus is between nothing and nothing

C. One is 90% confident that the proportion of students who eat cauliflower on Jane's campus is between nothing and nothing

D. There is a 90% chance that the proportion of students who eat cauliflower in Jane's sample is between nothing and nothing

2. In a poll, 69% of the people polled answered yes to the question "Are you in favor of the death penalty for a person convicted of murder?" The margin of error in the poll was 3%, and the estimate was made with 95% confidence. At least how many people were surveyed?

.

The minimum number of surveyed people was ?