Question
1. Parallax plays a part in measuring the internodal distances in Part 2. Describe in detail how measurements were made to minimize this effect. If
1. Parallax plays a part in measuring the internodal distances in Part 2. Describe in detail how measurements were made to minimize this effect. If an amount of uncertainty in measuring the internodal distances is to be considered what would be a reasonable amount. Explain why this amount was chosen.
2. If a thicker string was used in this experiment how would this affect the different parts of the experiment? Which quantities would be affected and how would they be affected?
3. As you increased the tension on the string in part 3 it may have caused a minor stretching of the string, thus lowering the linear density of the string. How does this affect the slope of the line drawn on the graph compared to using an ideal string which does not stretch?
4. Using equation 2 determine the velocities of the waves on the string for each of n = 3.5, 2.5, 1.5, and 1.0 from part 3. (show work)
M C E F G H 1 Experiment: Vibrating String - Melde's Experiment Part 1 Using the Sample String in the lab room determine the linear density of the string Sample String Sample String Length Mass 181.3 0.45 181.2 0.452 181.3 0.451 10 181.2 0.454 11 181. 0.452 12 13 Average Sample Average Sample 14 String Length String Mass 15 181.26 0.4524 16 17 Linear Density of Sample String 0.002495862 Part 2: Determine the frequency from measuring the internodal distances Internodal Distance 17.5000 7.6000 30 17.6000 31 17.5000 32 17.5000 33 34 Average 35 Internodal Distance 36 17.5400 37 38 Wavelength String 39 Tension, T 40 35.0800 49000 41 42 Frequency, f 43 126.3072 44 45 46 Part 3: Determine the frequency from the changing of the tension on the string45 46 Part 3: Determine the frequency from the changing of the tension on the string Length of String measured from oscillator on the Apparatus to top of pulley 50 126.0000 51 52 n Total Mass VM 1 53 3.5 50.0000 7.0711 .2857 2.5 100.0000 10.0000 .4000 1.5 300.0000 7.3205 |4999' 1.0 700.0000 26.4575 1.0000 Mass by 1 1.2000 y=0.0367x + 0.0294 1.0000 0.8000 0.6000 0.4000 0.2000 0.0000 0.0000 5.0000 10.000 0 15.000 0 20.000 0 25.000 0 30.000 0 Slope of Line Predictions from Graph and Actual Mass comparison from graph 9 89 99 89 9 0.0367 For n = 2.0, mass = 156.2500 For n = 2.0, actual mass = 164.4265 Frequency, f For n = 3.0, mass = 54.7600 For n = 3.0, actual mass = 68.5843 calculated from slope of line 135.5084 93 94Step by Step Solution
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