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(1 point) For each sequence an find a number k such that nkan has a finite non-zero limit. (This is of use, because by
(1 point) For each sequence an find a number k such that nkan has a finite non-zero limit. (This is of use, because by the limit comparison test the series an and n both converge or both n=1 n=1 diverge.) A. an (4+ 2n)-2 k = %3D . n k = 2n2- +2n+2 . n 6n +6n+2 k = 9. 2n2+2n+4 D. an 6n+6n+2 n k =
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Calculus Early Transcendentals
Authors: James Stewart
7th edition
538497904, 978-0538497909
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