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1. There is a very popular debate on the performance of the private universities (PUs) locating in Lisbon. Four of the famous private universities are

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1. There is a very popular debate on the performance of the private universities (PUs) locating in Lisbon. Four of the famous private universities are selected for a national efficiency measurement study. The performance of the PUs are evaluated based on the following inputs and outputs. Dataset related to these inputs and outputs are presented below. According to these, apply Input-Oriented Weighted and Envelopment DEA analysis only for PUI. Il: # of academicians 12: # of students 13: Tuition fee ($/year) 01: Number (#) of academic publications per year 02: # of graduates per year 03: Annual # of projects helded by In the table, X is calculated as 10 times PUS I1 12 13 01 02 03 the sum of the numbers in a Student PU1 X 19.0 38.000 250 11.500 Y ID. For instance, if a student ID is PU2 X+25 13.550 35.000 100 5.600 Y+10 118203001, X is found as "160" PU3 X-25 17.950 40.000 325 7.800 Y+20 ((1+1+8+2+0+3+0+0+1)*10]. PU4 X+40 12.750 25.000 180 7.880 Y+50 On the other hand, the value of Y can be obtained as summarizing the numbers in a Student ID and dividing the sum by 2. For the same student ID, Y is obtained as 8. 1. There is a very popular debate on the performance of the private universities (PUs) locating in Lisbon. Four of the famous private universities are selected for a national efficiency measurement study. The performance of the PUs are evaluated based on the following inputs and outputs. Dataset related to these inputs and outputs are presented below. According to these, apply Input-Oriented Weighted and Envelopment DEA analysis only for PUI. Il: # of academicians 12: # of students 13: Tuition fee ($/year) 01: Number (#) of academic publications per year 02: # of graduates per year 03: Annual # of projects helded by In the table, X is calculated as 10 times PUS I1 12 13 01 02 03 the sum of the numbers in a Student PU1 X 19.0 38.000 250 11.500 Y ID. For instance, if a student ID is PU2 X+25 13.550 35.000 100 5.600 Y+10 118203001, X is found as "160" PU3 X-25 17.950 40.000 325 7.800 Y+20 ((1+1+8+2+0+3+0+0+1)*10]. PU4 X+40 12.750 25.000 180 7.880 Y+50 On the other hand, the value of Y can be obtained as summarizing the numbers in a Student ID and dividing the sum by 2. For the same student ID, Y is obtained as 8

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