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1. This two-part question is worth twice as much as any of the one-part questions. Parts (a) and (b) below are each worth as much
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This two-part question is worth twice as much as any of the one-part questions. Parts (a) and (b) below are each worth as much as any other question in this exam. The contingency table below shows the results from a survey of 447 randomly selected adults who live in Macomb County. This survey was conducted to test the claim that adults' household sizes and age category are dependent. m-nn _ 46- 61 62 & older {a} At a: = 0.1, what is the critical value? 0 14.334 0 23.293 0 13.919 0 23.542 0 None of these {b} Find the expected frequency {E} used in the calculation of the X2 test statistic for the cell in the first row (18-30) and second column {2 people). 0 43.324 0 39.333 0 3.322 0 391.343 0 None of these Given belowis the data from 10 samples of 3 items each. In addition, the mean (i), range[R}, and proportion (p) of defective items\" have been calculated for you in the last three columns, and the averages of these three columns are also provided at the bottom of the table. *In this process, assume that "defective" items are those that have a value less than or equal to 7.7!\Given below are the sample means for fifteen samples consisting of five data values each. Assume that the mean of the sample means is ten and the computed values for the UCL and LCL of the x chart are 15 and 5, respectively. Below is the x chart. Is this process in statistical control? Why or why not? Select the best answer choice. Sample 1 2 3 4 6 8 9 10 11 12 13 14 15 Mean 6 10 6 9 8 13 12 12 9 12 13 14 12 17 16 15 UCL 14 13 12 11 10 centerline - LCI Co- 10 11 12 13 14 15 16 Q O No, because there are eight consecutive points all above or all below the centerline. O No, because there is a point lying beyond the upper or lower control limit. O No, because there is a pattern, trend, or cycle that is obviously not random. O No, because more than one of the answer choices above are correct. Yes, this process is within statistical controlStep by Step Solution
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