Question
1. X1 = Adult Open Trail Bike X2 = Adult Cityscape Bike X3 = Girls Sea Spite Bike X4 = Girls Trail Blazer Bike MAX
1. X1 = Adult Open Trail Bike X2 = Adult Cityscape Bike X3 = Girls Sea Spite Bike X4 = Girls Trail Blazer Bike MAX 100X1+120X2+150X3+125X4 S.T. X1+2X2+2X3+2X4<=108 Inventory Space 3X1+5X2+X4<=120 Assembly time X1+X3<=25 Manufacturing time X2+X3+X4=>50 Order for total bikes Use computer output to answer the following questions. a. Explain reduced cost for X2 (Adult Cityscape Bike). b. How much profit will change if the store had 10 more feet of inventory storage space? c. If 3 more bikes have been ordered, How much objective function value will increase or decrease? d. Suppose that profit per Adult Open Trail Bike (X1) decreases from $100 to $90 and profit per Adult Cityscape Bike (X2) increases from $120 to $124. Would the optimal solution will change? e. Company is considering using overtime to increase the available assembly time. What would you advise company to do regarding this option? Why?
2. X1 = Tuna Sandwich X2 = Ham Sandwich X3 = Turkey Sandwich MIN 4X1+5X2+6X3 S.T. 1) X1+X2+X3<=85 Available Tuna in pound 2) 3X1+4X2+2X3>=280 Available Ham in pound 3) 2X1+4X2+4X3<=320 Available Turkey in pound a. What is the optimal solution? b. Restaurant is considering buying 50 more pounds of Turkey. What would you advise regrading this option? c. Which constraints are binding? d. If the cost of per tuna sandwich decreased to $3.75, will the optimal solution change?
3. Problem 1(page 171) X1=# of TV ads X2=# of Radio ads X3=# of online ads Max 100,000x1+18,000x2+40,000x3=Z(Total number of audience) Subject to, 2,000x1+300x2+600x3<=18,200------budget X1<=10-------max TV ads X2<=20------Max Radio ads X3<=10-------max online ads -.5x1+.5x2-.5x3<=0-----max radio ads .9x1-.1x2-.1x3>=0-----Minimum TV ads X1,x2,x3>=0
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