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1.19 Prove: If s_(n) for all n and if both s_(n)->L and u_(n)->L then t_(n)->L as n->infty as well. (This is sometimes called the squeeze
1.19 Prove: If
s_(n) for all
n
and if both
s_(n)->L
and
u_(n)->L
then
t_(n)->L
as
n->\\\\infty
as well. (This is sometimes called the squeeze theorem or the sandwich theorem for sequences.)
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