13.3 Practice Treatment Treatment Treatment 32 44 35 30 43 38 30 44 37 26 46 38 32 48 42 Sample mean 30 45 38 Sample variance 6.00 4.00 6.50 a. At the o = 0.05 level of significance, can we reject the null hypothesis that the means of the three treatments are equal? Compute the values below (to 1 decimal, if necessary). Sum of Squares, Treatment 570 Sum of Squares, Error 66 0 Mean Squares, Treatment 2852 Mean Squares, Error 5.5 0 Calculate the value of the test statistic (to 2 decimals). 58.18 * The p-value is less than 0.01 What is your conclusion? Conclude that not all treatment means are equal b. Calculate the value of Fisher's LSD (to 2 decimals). 3.23 Use Fisher's LSD procedure to test whether there is a significant difference between the means for treatments A and B, treatments A and C, and treatments B and C. Use a = 0.05. Difference Absolute Value Conclusion TA - CB 18 Significant difference Significant difference 8 X Significant difference c. Use Fisher's LSD procedure to develop a 95% confidence interval estimate of the difference between the means of treatments A and B (to 2 decimals). Enter negative values as negative numbers. -18 72 0 -1 1 77 0