16.15. A car moves along the path seen below. Att = 2.0s the car is at A and has velocity Uy = 4.0%i+ 4.0 ?j. At t = 5.0s, it's at B with velocity , = 4.0?2 + 2.0? 10 2:29AM Tue Mar 12 L = 100% [42) { Back YA (o a Ao R TR IR Q M a. Find the x and y components of the average acceleration vector from 2.0s to 5.0s b. Write the average acceleration vector in terms of {, . Put the two velocity vectors in the picture tail to tail at the location A and then draw C_ia,,g 17.E. Below is the path of a moving object in two dimensions. The instantaneous position is givenby x =t3?, y = 2\\t + 1 and instantaneous velocity and acceleration are given by 0.5 0.75 0.25 vxl.S\\/?, Uy , axT ) ay__t_\\/f Assume standard metric units of m, m/s and m/s? a. Find the instantaneous position, instantaneous velocity, and instantaneous acceleration vectors at t = 2.5s. Give your answer as components. HELP: Use the 6 equations at the start of this problem and plug in 2.5 for time. b. Draw all three vectors in the diagram at t = 2.5s on the path seen above. HELP: recall that (i) the position vector is drawn with its tail at the origin and tip at the object. (ii) the instantaneous velocity vector is drawn tangent to the path in the direction of motion of the object. (iii) the instantaneous acceleration vector is drawn at the object. 11 Q Notifications = 100% [@#43) 2:29AM Tue Mar 12 eoe { Back YA (o a Ao R LRI Oy N c. From the geometry of the vector @ you drew in step (b), state if the object is speeding up or slowing down and which direction it is turning at that instant. 18.16 (a). Seen is a view from above a man who is jogging and his instantaneous velocity and instantaneous acceleration at some instant t = t;. Resolve a two different ways as directed. Qu QU X : > X (b). Which picture case 1 or case 2 is relevant to determining if the man is speeding up or slowing down and which way he'll turn? Is he speeding up or slowing down at t;? Which way will he turn soon after t; (left or right)? 12 Q Notifications