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1.In a multiple-factor Chi-square test, the expected frequencies are: A.the sub-totals for each row and column in the table. B.values taken directly from the table.

1.In a multiple-factor Chi-square test, the expected frequencies are:

A.the sub-totals for each row and column in the table.

B.values taken directly from the table.

C.calculated by multiplying the row marginal totals by the column marginal totals and dividing by the grand total.

D.equal to the sum of the row marginal total and the column marginal total.

2.The sub-totals for each row and column in a Chi-Square test are termed:

A.the sum of squares

B.the observed cells

C.the Chi-Square degrees of freedom

D.the marginals

E.the Contingency Values

3.Calculate the Chi-Square value for the following variables:

Landfalling hurricanes with male vs. female names:

Male: 21Female: 18

Non-landfalling hurricanes with male vs. female names:

Male: 17Female: 23

A.0.53

B.1.02

C.6.34

D.11.49

E.18.37

4.In a Chi-Square test, how many degrees of freedom would you have in a 4 by 4 table testing the relationship between flood risk (extreme risk, high risk, moderate risk, low risk) and land cover type (urban, forest, grassland, mixed crops)?Would this be a one or a two-tailed test?

A.9; one-tailed

B.6; two-tailed

C.9; two-tailed

D.6; one-tailed

5.The formula to calculate the Chi-Square value is essentially:

A. The sum of (observed frequency-expected frequency) squared /observed frequency

B. The observed group variance / calculated group variance

C. The sum of (observed frequency-expected frequency) squared / expected frequency

D. The expected frequency - the observed frequency summed and then squared

6.In the Chi-Square test, the Observed frequencies are:

A.data values given (or collected etc.) and taken directly from the contingency table

B.data that are calculated by multiplying the row marginal by the column marginal and dividing by the grand total

C.the sub-totals for each row and column in the table

D.equal to the sum of the marginals of the columns

7.What is the main purpose of the Chi-Square test?

A.To calculate if the sample mean comes from a population that is different from the population represented.

B.To calculate if the ratio of the between-group variance to within-group variance is greater than 1.

C.To calculate if the mean of one independent sample represents a population that is different from the second population.

D.To calculate if the frequencies in the tables are substantially different from the frequencies that you would expect to see in the table based upon probability.

8.Your calculated Chi-Square value is -12.992. Your critical value from the table is 5.991.What do you conclude?

A.you reject your null hypothesis because the absolute value of the calculated value is larger than the critical value

B.you fail to reject your null because the Chi-square value is negative and it is lower than the critical value

C.you reject your null because a Chi-Square value over 10 is extremely large and indicative of some process other than chance

D.because your calculated value is negative, you must have made an error somewhere and will need to redo the calculations

9.For which of the following would a Chi-Square test be BEST used:

A.To see if the rank of coldest temperatures [deg. C] is related to the rank of highest pressure [mb]

B.To see if there is a relationship between cloud type in various locations [cirrus, altocumulus, stratus] and water phase [ice vs. liquid vs. vapor]

C.To predict the rainfall threshold [in inches] at which peak streamflow [cubic ft per sec] occurs in a particular basin

D.To see if there is a relationship between sea surface temperatures [deg. F] and hurricaneintensity [pressure in mb]

10.In a two variable Chi-Square test, how would you calculate degrees of freedom for the following table: 3 columns and 3 rows?What would your Chi-Square table value be at the 0.01 significance level?

A.(number of rows) + (number of columns); 18.475

B.(number of rows) x (number of columns); 23.209

C.(number of rows -1) x (number of columns -1); 13.277

D.(number of cases -1); 18.307

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