$\frac{(2\mathrm{.}15{10}^{-4}\frac{\text{m}\text{o}\text{l}}{L}{)}^2(3\mathrm{.}3{10}^{-3}\frac{\text{m}\text{o}\text{l}}{L})}{(7\mathrm{.}79{10}^{-5}\frac{\text{m}\text{o}\text{l}}{L})(1\mathrm{.}93{10}^{-2}\frac{\text{m}\text{o}\text{l}}{L}{)}^3}=,10,\frac{L}{m}ol$