2 2 (1 point) If vi and V2 = are eigenvectors of a matrix Al corresponding to the eigenvalues 11 = 5 and 12 = 3respectively, Jan w40 then Ali + 12) = and A(-371) = (1 point) Consider the following Gauss elimination: 3 A 1 0 0 08 O A 0 0 1 0 1 0 EA 1 0 0 -3 0 E2E A 1 1 0 0 0 1 0 E3E2E1A = 0 0 8 2 -3 0 7 0 0 -7 -4 E1 E2 E3 E4 What is the determinant of Al? det(A) =