$25\mathrm{.}0mL$ of $0\mathrm{.}350$MNaOH $($MWt $40\mathrm{.}0\frac{g}{?}$ onol$)$ are added to $45\mathrm{.}0mL$ of $0\mathrm{.}125M$ copper $($it$)$ sulfate $(M{W}_t$:$159\mathrm{.}6\frac{g}{m}ol).$ How many grams of copper $(11)$ hydroxide $($MW$/$: $99\mathrm{.}6\frac{g}{m}ol)$ will precipitate?

a$.0\mathrm{.}560g$

b$.0\mathrm{.}275g$

c$.0\mathrm{.}854g$

d$.0\mathrm{.}436g$

e$.0\mathrm{.}697g$