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2) [6 pts) Fill in the blanks in the MIPS code segment to implement the following if-else structure: if (i != j) h = i
2) [6 pts) Fill in the blanks in the MIPS code segment to implement the following "if-else" structure: if (i != j) h = i + j else h = i - j MIPS code (assume i and j are already stored in $t4 and $t5, respectively. Store the result h in $t 3. Ignore any overflow.): lab1 beg add j lab1: sub lab2
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