2. 7/20 pts. A tank contains 500 m. of salt solution, with a salt concentration of 10 kg salt/m'. At time = 0, salt-free water starts to flow into the tank at a rate of 6 m/min. Simultaneously, salt solution flows out of the tank at 6 m /min, so that the volume of the solution is always Soom'. A mixer in the tank keeps the concentration of salt in the entire tank uniform so that the concentration in the effluent is the same as the concentration in the tank. a. What is the concentration in the effluent as a function of time? Show the resulting numerical values and their dimensions. Hint: -a -y = In (1) = -a(x2 x3) 315 pts. Arcaniation of sult = dovr dt 6m3/min 3 dev ('(t) = => 27 500 C(E)= Kexp d 250 4 t 250 K-> ((0) = 10 - K:10 b. What is the concentration at t = 10 minutes? 5/5 pts .(10) 250 (19= 1020 ( anse) => (650) = 408xPC 0) ) exp 25 25010 (10exp(- | ((10) = 1.0964781