2. Apply one iteration of Newton's Method to the given f with the given initial 131. (a) f(1:) = ,'3 9, T1 2 I1 (b) f(1:) = .1:2 9,1:1: (e) f(1:) = .133 51:+l I1: ((1) f(1:) = .163 5.1: +1: .T'l =1 (e) f(1:) = .163 2.1: + 2 with 1:1 2 0 (f) f(1:) = 1"3 21' + 2 \"1th 1'1: (g) f(1:) = tan(1:) 21: with 1:1 2 1