2 We have p1(a) = p2(a) = 3 and p3(a) = 0, so p(a) = 6. We have p1(b) = p2(b) = 2 and p3(b) = 3, so p(b) = 7. We have p1(c) = p2(c) = 1 and p3(c) = 2, so p(c) = 4. C d Therefore, according to the Borda rule, alternative b is selected