2.4-1. Shear Stress in Soybean Oil. Using Fig. 2.4-1, the distance between the two parallel plates is 0.00914 m and the lower plate is being pulled at a relative velocity of 0.366 m/s greater than the top plate. The fluid used is soybean oil with viscosity of 4 x 10-? Pas at 303 K (Appendix A.4). (a) Calculate the shear stress t and the shear rate using lb force, it, and s units. (b) Repeat, using SI units. (c) If glycerol at 293 K having a viscosity of 1.069 kg/m s is used instead of soybean oil, what relative velocity in m/s is needed using the same distance between plates so that the same shear stress is obtained as in part (a)? Also, what is the new shear rate? Ans. (a) Shear stress = 3.34 x 10-? 1by/ft?, shear rate = 40.0 s'; (b) 1.60 N/m; (c) relative velocity = 0.01369 m/s, shear rate = 1.50 s-4 Ay F, force