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26 0/ 1 point Q1-2. Under CNLRM you obtained the following regression result. Y = 2530.9 + 1.87X; se = (830.2) (0.76) n=22 Q1. Test
26 0/ 1 point Q1-2. Under CNLRM you obtained the following regression result. Y = 2530.9 + 1.87X; se = (830.2) (0.76) n=22 Q1. Test the hypothesis that the coefficient of X, is equal to 1 at 5% significance level. O Since test statistic is 1.14, we reject the null hypothesis. O Since test statistic is 1.14, we cannot reject the null hypothesis. O Since test statistic is 2.46, we reject the null hypothesis. O Since test statistic is 2.46, we cannot reject the null hypothesis. O Since test statistic is 3.05, we reject the null hypothesis.Q2. Now we want to test the hypothesis that the coefficient of X, is equal to 0. Within what range is the p-value most likely lying? (Hint: For a two-tail test, the p-value is the sum of the areas under the curve of the t-distribution beyond both the observed t-statistic and the negative of the observed t-statistic.) O Since test statistic is 2.46, p-value is between 0.025 and 0.01. O Since test statistic is 2.46, p-value is between 0.05 and 0.02. O Since test statistic is 1.14, p-value is greater than 0.1. O Since test statistic is 1.14, p-value is greater than 0.2. O We cannot specify the range where the p-value is lying
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