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3) At 200C the equilibrium constant for the reaction below is Ky = 12.0. CO2(g) + NO(g) 3 CO(g) + NO2(g) a) If 0.60 atm

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3) At 200C the equilibrium constant for the reaction below is Ky = 12.0. CO2(g) + NO(g) 3 CO(g) + NO2(g) a) If 0.60 atm CO2 and 0.60 atm NO are placed in a 10.0-L reaction vessel, what is the equilibrium pressure of CO? CO2(g) + NO CO + NO268) I E b) If a second equilibrium was set with the same total pressure of reactant gases, but the pressures are 0.30 atm CO2 and 0.90 atm NO, would the change in concentration (x) be the same? Explain your reasoning without using a calculation

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