3. Write the equivalent structural verilog code for the procedural code below that does a y = 1 + x3 function. input (2:0) x; output [6:0] y; reg (6:0) y; wire [2:0) x; always @(x) begin y=0; case(x) 3'5000:y=1; 3'b001: y=2; 3'b010: y=9; 3'b011: y=28; 3'b100: y=65; default: y=0; end case end 3. Write the equivalent structural verilog code for the procedural code below that does a y = 1 + x3 function. input (2:0) x; output [6:0] y; reg (6:0) y; wire [2:0) x; always @(x) begin y=0; case(x) 3'5000:y=1; 3'b001: y=2; 3'b010: y=9; 3'b011: y=28; 3'b100: y=65; default: y=0; end case end