3A. Determine the Molarity of the Sodium ion in a solution of Na2SO4.10H20 if you add 3.041 grams to a final volume of 150 ml.

Add 3.041 g of Na2SO4.10H20 in a beaker

pour upto 150ml of water to achieve 0.063 Molar.

Calculation

Na2SO4.10H20 MW = 322.03g/mol

Grams = 3.041 g

Vf = 150ml = 0.15L

M= mols of solute/ L of solution

(3.041g/1) (1mol/ 332.2g) = 0.00915mol Na2SO4.10H20

0.00915mol Na2SO4.10H20/ .15l= 0.061 M

2 Na = 2*0.061mol/L = 0.126 mol/L

Answer the question below

Make a 1:100 solution of Na2SO4.10H20 in 100 ml of water from your previous solution. What is the final concentration of the Sodium Ion?