Question
3CaCl2(aq)+2Na3PO4(aq)--->Ca3[PO4]2(s)+6NaCl(aq) masa molar CaCl2=110.97g/mol masa molar Na3PO4=163,87 g/mol masa molar Ca3(PO4)2=310,07 g/mol masa molar NaCl+ 58,43 g/mol Si se permite que 5,0 gramos de cloruro
3CaCl2(aq)+2Na3PO4(aq)--->Ca3[PO4]2(s)+6NaCl(aq)
masa molar CaCl2=110.97g/mol
masa molar Na3PO4=163,87 g/mol
masa molar Ca3(PO4)2=310,07 g/mol
masa molar NaCl+ 58,43 g/mol
Si se permite que 5,0 gramos de cloruro de calcio reaccionen con 5,0 gramos de fosfato de sodio, cuntos gramos del producto, fosfato de calcio, se pueden producir?
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Chemical Principles
Authors: Steven S. Zumdahl, Donald J. DeCoste
7th edition
9781133109235, 1111580650, 978-1111580650
