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4. [0/1 Points] DETAILS PREVIOUS ANSWERS MY NOTES PRACTICE ANOTHER Math 110 Course Resources - Applications of Definite Integrals Course Packet on the area between

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4. [0/1 Points] DETAILS PREVIOUS ANSWERS MY NOTES PRACTICE ANOTHER Math 110 Course Resources - Applications of Definite Integrals Course Packet on the area between two curves Determine the area of the region bounded by y = x2 - 4x and y = 0 on the interval [-2,2]. Area = 5.34 X 5. [1/1 Points] DETAILS PREVIOUS ANSWERS MY NOTES Math 110 Course Resources - Applications of Definite Integrals Course Packet on the area between two curves Determine the area of the region bounded by y = x2 and y = 3x on the interval [0,6]. Area = 27 6. [0/1 Points] DETAILS PREVIOUS ANSWERS MY NOTES Math 110 Course Resources Applications of Definite Integrals Course Packet on the area between two curves calcPad + Operations Determine the area of the region bounded by y = efx and y = - on the interval [1,2]. Functions X Symbols Area = Relations Sets VO O! Vectors Submit Answer Viewing Saved Work Revert to Last Response Trig Greek 7. [0/1 Points] DETAILS PREVIOUS ANSWERS MY NOTES PRACTICE ANO Help Math 110 Course Resources - Applications of Definite Integrals Course Packet on the area between two curves Determine the area of the region bounded by y = > and y = @ on the interval [1,10]. Area = 8. [0/1 Points] DETAILS PREVIOUS ANSWERS MY NOTES Math 110 Course Resources Applications of Definite Integrals Course Packet on the area between two curves Determine the area of the region bounded by f(x) = v x and g(x) = x/2 on the interval [0,16]. Area = X 9. [-/1 Points] DETAILS MY NOTES Math 110 Course Resources - Applications of Definite Integrals Course Packet on the area between two curves Determine the area of the region bounded by y =- x2 +5 " and y = 0 on the interval [-3,5]. Area 10. [0/1 Points] DETAILS PREVIOUS ANSWERS MY NOTES Math 110 Course Resources - Applications of Definite Integrals Course Packet on the area between two curves Determine the area of the region bounded by y = (x - 5)ex - 30% and y = 0 on the interval [0,10]. Area = 0

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