4 18 points op-amps in series Consider the following circuit: V_A V_B 8 ww 2 www 6 KQ www 3 10V 4kQ ww + op-amp 1. 10V Node A V_0 3 4.1 8 points Derive a expression on Vo in terms of A and B. Assume |Vo| < 10V. 4.3 6 points Given VA = 3* cos(40*t) and VB = 9V Find minimum voltage on Vo and maximum voltage on VR. 5V 2kQ op-amp 2 AC voltage source VA is given as V = A*cos(@ t) and DC voltage source VB is given as VB = B. The two DC voltage source above and below the op-amp 1 provides 10V and the DC voltage source above the op-amp 2 provides 5V. Node A which is the left side of the 3K 2 is represented as Vo. 4.2 4 points Derive a expression on voltage across Rout which is VR in terms of Vo. Assume |VR| < 5V. R out V_R