$4$

$5$

$6$

$7$

How many grams of solid barium sulfate form when $28\mathrm{.}0mL$ of $0\mathrm{.}780M$ barium chloride reacts with $50\mathrm{.}0mL$ of $0\mathrm{.}280M$ sodium sulfate? Aqueous sodium chloride also forms in this reaction. Be sure your answer has the correct number of significant figures.

g

$10$