5. (06.09 MC) Use integration by parts to fill in the table for v2xInxax, such that integration can be completed. (1 point) U= ? dv = ? du = ? v=? = 2x, du= dx dv = Inxdx, v = xInx - x 2:2x Ou=2x, due 2V/2x3 dx, dv = Inxdx, v = - 3 X ( = Inx, du = -, dv = \\2xdx. v 2V2x3 X 3 O u = Inx, du = , dv = \\2xdx. V= 1 X 2 2x3. (06.09 MC) Which of the following represents the correct integration by parts for | xsin(2x) dx? (1 point) -1xcos(2x) + - cos(2x) dx [ xsin(2x) dx = . sin(2x)-[x'cos(2x) dx [ xsin(2x)dx = sin(2x)+ _[x'cos(2x) dx -* *cos (2x) - [ cos ( 2x) dx 4. (06.09 MC) The function fhas a continuous second derivative. If f (2) = f (0) use the incomplete graph of f to evaluate J (2x + 3)"(x)ex. (1 point) 10 (2. 7.309) (1. 2.718) (0, 1) 0.5 0.5 1.5 25 48.723 42.334 35.945 132 4431. (06.09 MC) Evaluate [ x23* dx. (1 point) O x2.3* 2x.3* 2.3x +C In 3 In 3 (In 3)2 O x3 .3* In3.x3.3x -+C 3 3 O x3.3* In3. x3.3x -+C 3 3 O x2.3* 2x. 3* 2.3x +C In 3 (In 3)2 (In3)3 2. (06.09 MC) Evaluate (2ev2x dx. (1 point) O e2 - 1 O 202 + 2 O 2e2 O e2 +1