5) 20 pts. Newton showed that the air resistance on a falling object with circular cross section should be approximately % pir v"where p = 1.2 kg/m is the density of the air. Find the terminal speed for a 56-kg sky diver assuming that his cross-sectional area is equivalent to that of a disk of radius 0.3-meters.PHYSICS 105 EQUATION SHEET g = 9.8 m/sec/sec At g = 32.2 ft/sec/sec dawg = Av At dt a, = dy dt a = dv v = V. + at At (1-1,) = Vat +1/2at a Try = Av At v2 = vg + 2a(x-x,) tan 0 = vi ] gr v+ Vo V= 2 Work = [F - dF (x - x ) = vt Work =1/2mv? -1/2mv; WI = mg EF = ma Up = mgy f. =U.FN f, Su, FN . 2 e(v, - v2) = (v2 -v;) S, SH,F N W =mg