5. How much wil the temperahure of a 00 (180 ol of cofien at 85 ' 7 be placed in the cethee and both are allowed se resh fhe lowe tercensine? Aosume that the catree has the same derity and ieesile hest as miter. the sate temperabure were placed in A refrigerator. Nhar 30 minutre the 500mL. botite of water had cooled to the lemperales of the ritigerats. An bour later, the 24. of witer had cooled bo the sarse teeperatis. 0 the surpe amount of heat aince they bepan s anded at the sume temperabures. Student B said. the A. L bofte of wher lost more theak because there was more waler. Studont C said be asoomt boltie of wathe lost more heat because it cooled quicker. Studert D maid it is net. possible io answer this question since we do not know the intat I final. temperasutes of the water. Which stubent is exnect? Deterte thi entor in each of the othet answors. 7. When 50.0g of 0.200MNuck Naq) at 24.1 'C is assed se 100.0g of 0.100M AgNOS(ag) at 24.1C in a calorimetet the senpertare increstes to 252C as AgCl(s) formt. Assuming the specife hest of the solution and products is 4.20H/9C. calculate the heat d produced. 6. A.2500-mL botte of water at room temperature and a 4L botle of water at the same temperature ware placed in at relrigoratoc. After 30 minutes, the 500 -mL bottie of water had cooled to the temperature of the refrigerator: An hour later, the 2-L of water had cooled to the same temgerature. Q : Which water: sample lost the most heat? Student A said both botties lost the same amount of heat since they began 8 ended at the same temperatures, Student B said the 4-L bottlo of water lost more heat because there was more water. Student C said the 2500-mL bottle of water lost more heat because it cooled quicker. Shupent 0 said it is not possible to answor this question since we do not know the initial 8 final temperatures of the water. Which student is correct? Describe the ertor in each of the other answers. 7. When 50.0g of 0.200MNaCl(aq) at 24.1C is added to 100.0g of 0.100M AgNO3(aq) at 24.1C in a calorimeter, the temperature increases to 25.2C as AgCl(s) forms. Assuming the specific heat of the solution and products is 4.20JgC, calculate the heat(J) produced