5. The cost of a Starbucks Grande Latte varies from city to city. However, the variation among prices remains steady with a standard deviation of $1.25. Research was done to test the claim that the mean cost of a Starbucks Grande Latte is at least $4.25. Twenty (20) Starbucks Grande Latte yield a mean cost of $3.65 with a standard deviation of $0.35. What is the test statistic (z score)?

4.25

-1.75

2.35

1.25

6.UIW did a student satisfaction survey that was emailed to 1089 servicemembers. 72 of them answered the survey. We are interested in further researching about the population proportion of servicemembers who answered the survey. Identify x, n and p'.

x = 72

n = 1089

p' = 0.07

x = 1089

n = 72

p' = -14.13

x = 1089

n = 72

p' = 15.13

x = 72

n = 1089

p' = 0.93

7.The grades on the midterm follow a normal distribution:

= 86.09 and

mu, equals, 67

\sigma = 2.5

=10.69

Student B scores 99 on the exam. Find the z-score for student B's exam grade. Round the result to two decimal places.

z = -1. 21

z = 12.10

z = 0.12

z = 1.21

8.The cost of a Starbucks Grande Latte varies from city to city. However, the variation among prices remains steady with a standard deviation of $1.25. Research was done to test the claim that the mean cost of a Starbucks Grande Latte is at least $4.25. Twenty (20) Starbucks Grande Latte yield a mean cost of $3.65 with a standard deviation of $0.35. By using an 8% level, what is your decision?

A.Reject the Ho because the p-value is equal to the alpha value

B.Fail to reject Ho because the p-value is less than the alpha value

C.None of the above

D.Reject Ho because the p-value is less than the alpha value

9.By using the same mean (86.09) and standard deviation (10.69), find the probability that student A scores between 70 and 90 on the final exam? Round the result to two decimal places.

P(70

P(70

P(70

P(70

10.The grades on the midterm follow a normal distribution:

= 86.09 and

mu, equals, 67

\sigma = 2.5

=10.69

Student A score 82 on the exam. Find the z-score for student A's exam grade. Round the result to two decimal places.

z = 3.80

z = 0.03

z = 0.38

z = - 0.38

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