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5.0 Points Question 1 of 20 If three people are selected at random, nd the probability that at least two of them have the same
5.0 Points Question 1 of 20 If three people are selected at random, nd the probability that at least two of them have the same birthday. A. 0.07 B. 0.02 C. 0.01 D. 0.001 Question 2 of 20 Find the indicated term of the arithmetic sequence with first term, a 1, and common difference, d. 5.0 Points Find a200 when a1 = -40, d = 5 A. 865 B. 955 C. 678 D. 895 Question 3 of 20 5.0 Points Use the Binomial Theorem to expand the following binomial and express the result in simplied form. (x2 + 2y)4 A. x8 + 8x6 y + 24x4 y2 + 32x2 y3 + 16y4 B. x8 + 8x6 y + 20x4 y2 + 30x2 y3 + 15y4 C. x8 + 18x6 y + 34x4 y2 + 42x2 y3 + 16y4 D. x8 + 8x6 y + 14x4 y2 + 22x2 y3 + 26y4 Question 4 of 20 5.0 Points You volunteer to help drive children at a charity event to the zoo, but you can t only 8 of the 17 children present in your van. How many different groups of 8 children can you drive? A. 32,317 groups B. 23,330 groups C. 24,310 groups D. 25,410 groups Question 5 of 20 5.0 Points How large a group is needed to give a 0.5 chance of at least two people having the same birthday? A. 13 people B. 23 people C. 47 people D. 28 people Question 6 of 20 5.0 Points Use the formula for the sum of the rst n terms of a geometric sequence to solve the following. Find the sum of the rst 11 terms of the geometric sequence: 3, -6, 12, -24 . . . A. 1045 B. 2108 C. 10478 D. 2049 Question 7 of 20 5.0 Points Write the rst four terms of the following sequence whose general term is given. an = 3n A. 3, 9, 27, 81 B. 4, 10, 23, 91 C. 5, 9, 17, 31 D. 4, 10, 22, 41 Question 8 of 20 5.0 Points k2 + 3k + 2 = (k2 + k) + 2 ( __________ ) A. k + 5 B. k + 1 C. k + 3 D. k + 2 Question 9 of 20 5.0 Points Write the rst six terms of the following arithmetic sequence. an = an-1 - 10, a1 = 30 A. 40, 30, 20, 0, -20, -10 B. 60, 40, 30, 0, -15, -10 C. 20, 10, 0, 0, -15, -20 D. 30, 20, 10, 0, -10, -20 Question 10 of 20 5.0 Points If three people are selected at random, nd the probability that they all have different birthdays. A. 365/365 * 365/364 * 363/365 0.98 B. 365/364 * 364/365 * 363/364 0.99 C. 365/365 * 365/363 * 363/365 0.99 D. 365/365 * 364/365 * 363/365 0.99 Question 11 of 20 5.0 Points Write the rst four terms of the following sequence whose general term is given. an = (-3)n A. -4, 9, -25, 31 B. -5, 9, -27, 41 C. -2, 8, -17, 81 D. -3, 9, -27, 81 Question 12 of 20 5.0 Points Use the Binomial Theorem to expand the following binomial and express the result in simplied form. (2x3 - 1)4 A. 14x12 - 22x9 + 14x6 - 6x3 + 1 B. 16x12 - 32x9 + 24x6 - 8x3 + 1 C. 15x12 - 16x9 + 34x6 - 10x3 + 1 D. 26x12 - 42x9 + 34x6 - 18x3 + 1 Question 13 of 20 5.0 Points The following are dened using recursion formulas. Write the rst four terms of each sequence. a1 = 3 and an = 4an-1 for n 2 A. 3, 12, 48, 192 B. 4, 11, 58, 92 C. 3, 14, 79, 123 D. 5, 14, 47, 177 Question 14 of 20 5.0 Points The following are dened using recursion formulas. Write the rst four terms of each sequence. a1 = 7 and an = an-1 + 5 for n 2 A. 8, 13, 21, 22 B. 7, 12, 17, 22 C. 6, 14, 18, 21 D. 4, 11, 17, 20 Question 15 of 20 5.0 Points Find the indicated term of the arithmetic sequence with rst term, a1, and common difference, d. Find a6 when a1 = 13, d = 4 A. 36 B. 63 C. 43 D. 33 Question 16 of 20 5.0 Points An election ballot asks voters to select three city commissioners from a group of six candidates. In how many ways can this be done? A. 20 ways B. 30 ways C. 10 ways D. 15 ways Question 17 of 20 5.0 Points If two people are selected at random, the probability that they do not have the same birthday (day and month) is 365/365 * 364/365. (Ignore leap years and assume 365 days in a year.) A. The rst person can have any birthday in the year. The second person can have all but one birthday. B. The second person can have any birthday in the year. The rst person can have all but one birthday. C. The rst person cannot a birthday in the year. The second person can have all but one birthday. D. The rst person can have any birthday in the year. The second cannot have all but one birthday. Question 18 of 20 5.0 Points If 20 people are selected at random, nd the probability that at least 2 of them have the same birthday. A. 0.31 B. 0.42 C. 0.45 D. 0.41 Question 19 of 20 5.0 Points Use the Binomial Theorem to nd a polynomial expansion for the following function. f1(x) = (x - 2)4 A. f1(x) = x4 - 5x3 + 14x2 - 42x + 26 B. f1(x) = x4 - 16x3 + 18x2 - 22x + 18 C. f1(x) = x4 - 18x3 + 24x2 - 28x + 16 D. f1(x) = x4 - 8x3 + 24x2 - 32x + 16 Question 20 of 20 5.0 Points To win at LOTTO in the state of Florida, one must correctly select 6 numbers from a collection of 53 numbers (1 through 53). The order in which the selection is made does not matter. How many different selections are possible? A. 32,957,326 selections B. 22,957,480 selections C. 28,957,680 selections D. 225,857,480 selections
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