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50 scientists who received a university degree were asked whether they have a cat. 30 of them have a cat. We want to test if

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50 scientists who received a university degree were asked whether they have a cat. 30 of them have a cat. We want to test if more than a half of highly educated people have a cat. Select a randomization distribution that would be appropriate for these data.

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Randomization Dotplot of PI - P1- Null Hypothesis: PI = P2 Original Sample rumple - 1600 Group Count Sample OLeft Tail Two-Tail ! Right Tail Size Proportion 150 Group 1 30 50 0.600 Group 2 20 50 0.400 Group 10 1-Group 2 n/a 0.200 100 Randomization Sample 0.025 Sample 50 Group Count Size Proportion Group 1 27 50 0.540 Group 2 23 50 0.460 Group na 0.030 -0.30 -0.20 -0. 10 0.30 1-Group 2 null - 0 0.200Randomization Dotplot of Proportion Null hypothesis: p = 0.5 125 O Left Tail Two-Tail / Right Tail samples = 1060 Original Sample meen = 0 501 Count Sample Size and error = 0.071 Proportion 30 50 0.600 100 Randomization Sample 75 Count Sample Size Proportion 26 50 0.520 0.094 50 25 0 0.25 0.30 0.35 0.40 0.45 060 0.55 060 0.65 0.70 null = 0.5 0.600Randomization Dotplot of Proportion Null hypothesis: p = 0.5 125 Len Tail Two-Tail Right Tail samples = 1060 Original Sample meen = 0 501 Count Sample Size and error = 0.071 Proportion 30 50 0.600 100 Randomization Sample 75 Count Sample Size Proportion 22 50 0.440 0.941 50 25 0 0.25 0.30 0.35 0.40 0.45 060 0.55 060 0.65 0.70 null = 0.5 0.600Randomization Dotplot of Proportion Null hypothesis: p = 0.5 temples = 190g 125 O Left Tail Two-Tail Right Tail Original Sample mean = 0.501 Count Sample Size Proportion nid error = 0,071 30 50 0.600 100 Randomization Sample 75 Count Sample Size Proportion 31 50 0.620 0.094 0.812 0.094 50 25 0.25 0.30 0.35 0.410 0.45 0 60 0.55 0.65 0.70 null = 0.5 0.400 0.600

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