6. (7 points) Your Algebra I teacher probably drilled the quadratic formula into your head, which allows you to solve quadratic equations of the form ax2 + bx + c = 0. Not many people are aware that a formula also exists to solve cubic equations of the form x + px +q = 0 Using some algebraic wizardry, any cubic equation in the general form ax3 + bx2 + cx + d = 0 can be reduced to the form of equation (1). But let's not worry about how to do that here. Equation (1) is solvable using Cardano's formula, named after the Italian mathematician who allegedly derived it during the 1500s. The formula states that the solution is: (1) 27 27 (2) For now, let's consider only the real (i.e., non-imaginary) values of the quantities in (2). This means the formula will give only one of the three roots to (1). Write a program named CubicSolver.java that allows the user to enter values (potentially including decimals) for the coefficients p and q from (1). Your program should then compute and display the value of the solution x according to (2). Note that although using Math.pow with an exponent of 1.0/3 works for computing cube roots of positive numbers, Math.pow gives a result of NaN ("not a number") when computing the cube root of a negative number. Use Math.cbrt() instead; you can replace x with whatever you're trying to find the cube root of Example program run (underlined parts indicate what the user enters) Cubic Equation Solver Enter your coefficients: What is the value of p? 1 What is the value of q? 30 The solution X is -2.9999999999999742