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7) Approximately 15% of all people are left-handed. Consider a grouping of SIX people. (Use Table below) State the random variable. Write the probability distribution:

7) Approximately 15% of all people are left-handed. Consider a grouping of SIX people. (Use Table below)

  1. State the random variable.
  2. Write the probability distribution: P(x) for x = 0 to 6 (you can use software)
  3. Use the long binomial equation: P (k) = {n! / [k! *(n-k)!]} * pk * q(n-k)
  4. The P(x) values SHOULD be the SAME, whether from the Software or the Equation.
  5. Draw a histogram.
  6. Describe the shape of the histogram (is it skewed and if so + or - skew).
  7. Find the mean using = np.
  8. Find the variance using 2 = npq.
  9. Find the standard deviation = SQRT(npq)

Are the means, variance, and standard deviations from the Table below different from the binomial approximations? How so? Any reason for this you can think of?

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