(7%) Problem 9: A uniform rod with length L is free to rotate about an axis at ground level. The rod makes an angle with horizontal and is released from rest. 50% Part (a) Write an expression for the angular speed of the rod just before it strikes the ground. w = ((3 g sin (0) )/(L ) )| cos(a) sin(a) d m cos(Q) sin(Q) Y Submit n cos(0) sin (0) 0 L Hint Hints: 3 for a 0% deduction. Hints remaining: 0 -You will need to use conservation of energy to solve this problem. The potential energy of the rod before it is released is equal to the kinetic energy of the rod just before it hits the ground. -When determining the potential energy of the rod before it is released, you can assume all of the mass is acting at the center of the rod. You will need to use trigonometry to determine this height. -The final mechanical energy of the rod is all rotational and involves the moment of inertia of a rod rotating about one end. This value can be found in a table. ( ) 7 8 9 5 ^^|^||4 6 1 2 3 * / + 0 END VO BACKSPACE DEL CLEAR Feedback I give up! Feedback: 3% deduction per feedback. HOME Feedback: is available. Axis Grade Summary Deductions Potential 0% 100% Submissions Attempts remaining: (0% per attempt) detailed view 1 2 50% Part (b) If the rod has a length of 2.22 m and is dropped from an angle of 35.2 above the horizontal, what is the linear speed of the tip of the rod, in meters per second, just before the rod strikes the ground? vt = 3.06686 vt = 3.067 m/s X Attempts Remain 0% 0% (7%) Problem 9: A uniform rod with length L is free to rotate about an axis at ground level. The rod makes an angle with horizontal and is released from rest. 50% Part (a) Write an expression for the angular speed of the rod just before it strikes the ground. w = (( 3 g sin(0) )/(L ) )| cos(a) sin(a) d m cos(p) sin(Q) Y Submit n cos(0) sin(0) 0 L Hint Hints: 3 for a 0% deduction. Hints remaining: 0 -You will need to use conservation of energy to solve this problem. The potential energy of the rod before it is released is equal to the kinetic energy of the rod just before it hits the ground. -When determining the potential energy of the rod before it is released, you can assume all of the mass is acting at the center of the rod. You will need to use trigonometry to determine this height. -The final mechanical energy of the rod is all rotational and involves the moment of inertia of a rod rotating about one end. This value can be found in a table. ( ) 7 8 9 5 ^^|^||4 6 1 2 3 * / + 0 END VO BACKSPACE DEL CLEAR Feedback I give up! Feedback: 3% deduction per feedback. HOME Feedback: is available. Axis Grade Summary Deductions Potential 0% 100% Submissions Attempts remaining: (0% per attempt) detailed view 1 2 50% Part (b) If the rod has a length of 2.22 m and is dropped from an angle of 35.2 above the horizontal, what is the linear speed of the tip of the rod, in meters per second, just before the rod strikes the ground? Vt = 3.06686 vt = 3.067 m/s X Attempts Remain 0% 0%