[8 pts] We want to estimate the proportion of University of Montana/Missoula College students who support a new bill regarding minimum wage. We collect a simple random sample from 200 students, and 109 say they support the new bill. Construct a 95% confidence interval estimating the proportion of UM/MC students who support the bill. a. What is our sample statistic p? sample statistic = 0.545 = 54.5% b. Do we meet normality conditions (AKA the conditions of the Central Limit Theorem for proportions). Justify your response. np= = 200 0.545=109 n-p)=200 (1-0.545) 91 Since both the np and n(1-p) are greater than 10, we do meet the normality conditions. c. What is the margin of error for this confidence interval? (Explicitly show the pieces of your calculation so I can check for errors):