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9. [10] Using a 3 to 8 decoder, implement the function below: ABCD F 0000 0 0001 0 0010 1 0011 0 0100 1 1

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9. [10] Using a 3 to 8 decoder, implement the function below: ABCD F 0000 0 0001 0 0010 1 0011 0 0100 1 1 0101 0110 0 0111 1 1000 1 1001 1 1010 1 1 1011 1100 1 1101 0 1110 1 1111 0 10. [10] Using the same truth table as the previous problem, implement the function with a multiplexer

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