#9 Professor Jane Newman teaches an introductory calculus course. She wanted to test the belief that success in her course is affected by high school performance. She collected the randomly selected data listed below and ran an ANOVA test as shown below. The data in the \"High School Record\" table represents performance of the student in Jane's calculus. Anova: Single Factor High School Record Good Fair Poor 90 80 60 86 70 60 88 61 SUMMARY Su m 55 Groups Count Average Variance 52 62 80 73 437 87.4 23.8 7 484 69.1428571 4 117.142857 1 Poor 6 357 59.5 45.5 50 65 5 Fair 93 Good 70 83 ANOVA Source of Variation Between Groups 2162.44285 7 Within Groups a) SS 1025.55714 3 df MS F P-value F crit 2 1081.22142 9 15.8141567 6 0.00020221 4 3.68232034 4 15 68.3704761 9 If we set at 0.05, what would we conclude about the ANOVA test? State the null hypothesis Total 3188 17 and result clearly. Give a reason for your result